If it's not what You are looking for type in the equation solver your own equation and let us solve it.
21b^2+40b+16=0
a = 21; b = 40; c = +16;
Δ = b2-4ac
Δ = 402-4·21·16
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{256}=16$$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(40)-16}{2*21}=\frac{-56}{42} =-1+1/3 $$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(40)+16}{2*21}=\frac{-24}{42} =-4/7 $
| -6-y+4=0 | | X+4+6x-12=180 | | 3j+2=-2j-1+4j | | -16+4=-2(x+2) | | -12-y+4=0 | | 5/18+x/9=3 | | 8p-25+4p=-73 | | 8(3n+3)=6(6n+9)+2 | | 5(2w-4)+3=-4w-10 | | X-103=209-11x | | |-4.1+2x|=2.1 | | -4x+47=-4(x+6)+7 | | 8-(a+7)=a+40 | | -2(4g-3)=4(-g+2) | | -2x-12x=-17 | | 3/4x+1=1/4x-4 | | -4(5t-5t)+8t=5t-9 | | 12t=-135 | | 8-1(2a+7)=a+40 | | 7x-37=x+89 | | -12(x+9)=4(x+39) | | 12f+11=-9f+25 | | -12-2v=8(8v+7)-2 | | 6x-x=64 | | 9x+2-3x=-17-x | | 2(3-2c)=30 | | 7(w+4)=10w+7 | | x=2(-4,5)+7 | | 2z+5/6=3z+1/6 | | -2y-6=-2 | | Y-20=7(x-5) | | 3b-2-b+5=13 |